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y^2+12y-640=0
a = 1; b = 12; c = -640;
Δ = b2-4ac
Δ = 122-4·1·(-640)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-52}{2*1}=\frac{-64}{2} =-32 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+52}{2*1}=\frac{40}{2} =20 $
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